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`1/4``1/8``1/16``1/6`

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BSolution :

Suppose `n(lt1)` fraction of length is stretched to m times. <br> Then, `(1-n)l+(nl)m=1.5l` <br> or `nm-n=0.5` <br> `R=(rhol)/A=(rhol)/(V//l)(V=volume)` <br> `=(rhol^2)/V` <br> `R prop l^2` (if `V=`constant) <br> Now the second condition is <br> `(1-n)R+(nR)m^3=4R` <br>:.`m^2-n=3` ...........iii <br> Solving these two equations, we get <br> `n=1/8`